Phone number validation regular expression consist one plus sign in start and preceding digits

Question

I am trying to validate phone number but cannot.

My requirement is phone number consist only of digits and + (plus symbol). The + can be only the first character.

For example: +123456489

I am using this regular expression but it is not working:

/^\+(?:[0-9]??)$/

Thanks in advance.

The regex is `^\+?\d+$`. In HTML `pattern` attribute, it looks like `pattern="\+?\d+"`. If you need to limit the number of digits to a specific amount replace `\d+` with `\d{n}` where `n` is the exact number of digits you want. — Wiktor Stribiżew, Jul 28 '23 at 11:29

brandonscript · Answer 1 · 2014-01-10T16:49:34.200

16

I'd use this instead:

^\+?\d*$

Matches your + at the start, then any digit, dash, space, dot, or brackets.

See it in action: http://regex101.com/r/mS9gD7

edited Jan 10 '14 at 16:49

answered Jan 10 '14 at 16:37

brandonscript

68,675
32
163
220

2

only digit and plus sign is allowed. – Sami Jan 10 '14 at 16:40
3

@Sami in that case, even simpler: `^\+?\d*$` – brandonscript Jan 10 '14 at 16:49

score 9 · Answer 2 · answered Sep 07 '17 at 01:42

9

How about this?

^[\+\d]?(?:[\d-.\s()]*)$

works fine with bellow test cases:

You can test it here : https://regex101.com/r/mS9gD7/39

answered Sep 07 '17 at 01:42

tk_

16,415
8
80
90

phone numbers cannot start with - (dash) – hakki Apr 20 '22 at 13:02

Rahul Gupta · Answer 3 · 2018-12-25T08:43:33.660

8

If you only want to allow + sign and that is only at the beginning of the number and does not want to allow any other characters or symbols other that the digits, then try the below regex:

var regEx = /^[+]?\d+$/;
regEx.test("+123345"); // this will be true
regEx.test("++123345"); // this will be false
regEx.test("1+23345"); // this will be false
regEx.test("111222"); // this will be true

edited Dec 25 '18 at 08:43

answered Dec 25 '18 at 08:38

Rahul Gupta

9,775
7
56
69

score 2 · Answer 4 · edited Feb 17 '22 at 10:00

2

^\+[0-9]+$

Try the above regex. You can test here http://gskinner.com/RegExr/. Are you also looking to validate length?

edited Feb 17 '22 at 10:00

Wiktor Stribiżew

607,720
39
448
563

answered Jan 10 '14 at 16:38

Srb1313711

2,017
5
24
35

score 2 · Answer 5 · answered Dec 19 '19 at 06:58

2

^[0-9]+[0-9]*$ try this its working

answered Dec 19 '19 at 06:58

sarfaraz akhtar ansari

41
3

1

Thanks for your answer! Would be nice if you provided some explanation about how and why this works though. – Janis Jansen Dec 19 '19 at 07:02
There must be an optional `+` at the beginning and why 2 character class when only one is needed? – Toto Dec 19 '19 at 11:20

score -2 · Answer 6 · answered Jan 10 '14 at 16:43

-2

You can try this ^+[1-9]{1}[0-9]{10}$

answered Jan 10 '14 at 16:43

Henry

1,010
8
10

Why [1-9]{1} then [0-9]{10} after? – Srb1313711 Jan 10 '14 at 16:44
I guess it's to force the first digit to be different from 0. The '{1}' bit isn't doing much though. – Joao Raposo Jan 10 '14 at 16:49
Don't all phone number begin with a 0 though? – Srb1313711 Jan 10 '14 at 16:52
Well I don't know, but I think when you have +(plus sign) you don't have 0's. I just pointed out the meaning of that regex. – Joao Raposo Jan 10 '14 at 16:55
+ sign in the regex allow you use '+' instead of '00' – Henry Jan 10 '14 at 16:57
@HenryTshobo the deal was regarding '[1-9]{1}' and '[0-9]{10}' bits unless you want a number like +012345678 to be matched – Joao Raposo Jan 10 '14 at 17:02

Phone number validation regular expression consist one plus sign in start and preceding digits

6 Answers6