php.exe is not recognized as an external or internal command

Question

I am trying for create a new project in yii.When I execute the command "yiic webapp c:\wamp\www\testyii" shows the below error

"php.exe is not recognized as an internal or external command".

My environment variable path is "%path%;C:\wamp\bin\php\php5.4.16".

How do I solve this issue ?

How did you install PHP? via Wamp/xampp or by itself installer. — shgnInc, Apr 09 '14 at 07:41
Try this: http://stackoverflow.com/questions/18781997/php-exe-is-not-recognized-as-an-internal-or-external-command-operable-progr And also try the search function. — MichaelS, Apr 09 '14 at 07:43
before executing this command execute this one: `cd C:\\wamp\bin\php\php5.4.16` after that execute your command. — Code Lღver, Apr 09 '14 at 07:45

score 0 · Answer 1 · answered Apr 09 '14 at 07:42

0

set environment variable path like follow....

path =>...;C:\Projects\wamp\php;C:\Projects\wamp\yii\yiiframework;

and also include the YII framework path in your path variable

answered Apr 09 '14 at 07:42

user is using wamp server not xampp server. – Code Lღver Apr 09 '14 at 07:46
Yes, Thanks Broken Heart, i just gave the solution overall. Thanks anyways – opensource-developer Apr 09 '14 at 07:48
Added these C:\Projects\wamp\yii\yiiframework to variable again run that command "yiic webapp c:\wamp\www\testyii" shows the error "php.exe is recognized as an internal or external command". – user3514095 Apr 09 '14 at 08:09
did you use my variables as is like C:\Projects\wamp\yii\yiiframework t? or replaced / modified according to your path where the framework is set? – opensource-developer Apr 09 '14 at 09:26

score 0 · Answer 2 · edited Jun 14 '18 at 07:44

0

change file path, for example :

"%PHP_COMMAND%" == "" set PHP_COMMAND=E:\xampp\php\php.exe

edited Jun 14 '18 at 07:44

Sjon

answered Jun 14 '18 at 07:22

er.pawaramol

2 Answers2