Is there anything similar to a typeof in C++?

Question

I'm trying to create a constructor that states what type of objects it's storing. Is there any simple way to accomplish this? I was looking at decltype.

template <typename T>
MyVector<T>::MyVector(int setCap)
{
    m_ptr = new T[setCap];
    m_size = 0;
    m_capacity = setCap;
    string typeSet = decltype(T);
    cout << "New MyVector of type " << typeSet << " created\n";
}

Are you looking for [`typeid`](http://en.cppreference.com/w/cpp/language/typeid)? The output of `typeid(...).name()` may or may not spell out the type name in a way you find useful, that's implementation dependent. — Praetorian, Mar 13 '13 at 21:15
@thiefjack if you're using GCC you can demangle the name using the second answer to [this question](http://stackoverflow.com/questions/281818/unmangling-the-result-of-stdtype-infoname) (don't use the first, it's buggy) — Stephen Lin, Mar 13 '13 at 21:18
possible duplicate of [How do I get the type of a variable?](http://stackoverflow.com/questions/11310898/how-do-i-get-the-type-of-a-variable) — David G, Mar 14 '13 at 15:07

score 2 · Accepted Answer · answered Mar 13 '13 at 21:26

2

C++ has typeid:

#include <typeinfo>

std::cout << "The type is " << typeid(T).name();

answered Mar 13 '13 at 21:26

David G

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Is there anything similar to a typeof in C++?

1 Answers1