I want a string, which must be in parentheses () and separated with a comma , something like: (aaa),(bbbb),(cccccccc)
How could I match that using regular expression?
Asked
Active
Viewed 1.5k times
3
-
2Wish there was a regular expression to fix typos! – devnull Jun 06 '13 at 13:31
-
Whats "allowed" to be in between the () ? – Connor Tumbleson Jun 06 '13 at 13:32
-
You can use the pattern ^\([^(^)]+\)(,\([^(^)]+\))*$ Try for your self: https://regex101.com/r/cJj2ky/1 – Seb T May 25 '18 at 14:53
3 Answers
6
You can try this
^(?!,)(,?\(\w+\))+$
^ marks the beginning of string
$ marks the end of string
Both ^,$ are required else it would match in between
\w+ matches 1 to many of [a-zA-Z\d_]
,? would optionally match ,
^(?!,) would look for , at the beginning of string and if it finds it,it doesn't match further.If it doesn't find,it returns to the previous position i.e at the start of string
Anirudha
- 32,393
- 7
- 68
- 89
-
This will also accept a string starting with a comma though. ",(aaa)" would be accepted. – Vahlkron Jun 06 '13 at 13:45
-
-
-
Actually, it looks like it's accepting a comma inside the () also. "(,sdfs),(sdfsd)" is valid. – Vahlkron Jun 06 '13 at 13:51
-
-
-
3
0
This regex
\(([^\)])\)
will match everything that's inside parethenses. You can use it to find submatches or whatever you need.
I suggest you first tokenize, saving in different variables what's separated by commas, and then use the regular expression to match what's inside the parentheses.
blue
- 2,683
- 19
- 29
0
This should do it:
/^\(([^)])\1*\)(?:,\(([^)])\2*\))*$/
using backreferences for the repeated characters, escaped parenthesis around them, and allowing it to be followed by the same thing many times - delimited with commata. Altogether anchored on the whole string.
