Syntax Error in Python3

Question

I'm just starting to learn Python and I decided to start with 3.2

I'm trying some socket managing code and I get a syntax error. (The line works just fine in 2.7)

Any ideas?

        def __init__(self, (socket, address)):
  File "./main.py", line 16
    def __init__(self, (socket, address)):
                       ^
SyntaxError: invalid syntax

Martijn Pieters · Answer 1 · 2015-01-21T11:28:46.393

3

You cannot define a method with a tuple argument in Python 3. This was possible in Python 2 but removed. See PEP 3113 Removal of Tuple Parameter Unpacking.

The syntax made introspection hard, (even impossible for IronPython), was incompatible with other new argument syntax (annotations and keyword-only arguments), produced unhelpful error messages and was one of the least-known and least-used features of the language.

You'll have to do the unpacking in the method:

def __init__(self, socket_address):
    socket, address = socket_address

edited Jan 21 '15 at 11:28

answered May 19 '14 at 15:17

Martijn Pieters

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That's interesting - why did they do that? – MattDMo May 19 '14 at 15:17
@MattDMo: There is other new argument features (keyword-only arguments, annotations) that made this case hard to maintain and it was used *very* rarely. – Martijn Pieters May 19 '14 at 15:18

Syntax Error in Python3

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