Turn 1/0 to valid/invalid

Question

how i can turn in PHP the $validation output from 1/0 to the word "valid/invalid"? Do i need json_encode($validation) in this case?

    $json = json_decode($content, true);

    if ($json['error'] == NULL ) {
        $country = $json['result']['countryCode'];
        $vatNumber = $json['result']['vatNumber'];
        $validation = $json['result']['valid'];               

          echo "
          <dt>Valid:</dt>
          <dd>$validation</dd>
          <dt>VAT-Number:</dt>
          <dd>$country$vatNumber</dd>

        } else {
    echo "error";
    }

Thank you!

@sectus had a point in comments for @agro answer...I updated my answer to reflect a (secondary) validation `$validation === 1` in attempt to avoid non-desired valid returns. — CrandellWS, May 26 '14 at 09:36

agro · Answer 1 · 2014-05-27T07:45:20.457

0

how about this:

...
<dd>" . ($validation ? 'valid' : 'invalid') . "</dd>
...

or with a secondary check

...
<dd>" . ($validation == 1 ? 'valid' : 'invalid') . "</dd>
...

edited May 27 '14 at 07:45

answered May 26 '14 at 08:11

agro

206
1
2
7

better to be short and sweet as shown in this answer, which will get the same results as I suggested. – CrandellWS May 26 '14 at 08:15
What about precedence? – sectus May 26 '14 at 08:16
@sectus notice [example 4](http://php.net/language.operators.comparison#language.operators.comparison.ternary) as [mentioned](http://stackoverflow.com/a/6224443/1815624) is Non-obvious Ternary Behaviour and [user3675536](http://stackoverflow.com/users/3675536/user3675536) is obviously a beginner PHP programmer... – CrandellWS May 26 '14 at 08:53
@CrandellWS , reread answer. Try to reproduce code of the answer. Then think about operator precedence (concatenation and ternary). – sectus May 26 '14 at 09:03
@sectus I am not understanding as `$validation ? 'valid' : 'invalid'` is the same as `(($validation ? true : false) ? 'valid' : 'invalid'` only a problem if it wasn't a `1||0` `true || false` value... – CrandellWS May 26 '14 at 09:23
@sectus A consideration from a security point `((($validation === 1) ? true : false) ? 'valid' : 'invalid')` – CrandellWS May 26 '14 at 09:28
@CrandellWS , I am talking about operator precedence. Precedence of concationation is higher than precedence of ternary. So `echo "
" . $validation ? 'valid' : 'invalid' . "
";` would always output 'valid' instead of '
valid
' or of '
invalid
'. You need to add parentheses to change precedence: `echo "
" . ($validation ? 'valid' : 'invalid') . "
";` – sectus May 27 '14 at 01:39
he is right, so my first answer was wrong because of the precedence. `"
" . $validation ? 'valid' : 'invalid' . "
"` will be interpreted as `("
" . $validation) ? 'valid' : ('invalid' . "
")`. but my second one will work fine. – agro May 27 '14 at 07:43

CrandellWS · Accepted Answer · 2014-05-26T09:31:57.007

0

simple as 1 == true and 0 == false

if($validation === 1){
    $validation = 'valid';
} else {
    $validation = 'invalid';
}

have a reading of the php docs on boolean

edited May 26 '14 at 09:31

answered May 26 '14 at 08:14

CrandellWS

2,708
5
49
111

thank you for this incentive. helped me a lot. i will read about boolean. – user3675536 May 26 '14 at 08:23

score 0 · Answer 3 · answered May 26 '14 at 08:18

0

You could use an array:-

$validOrNot = ['invalid', 'valid'];

//some other code 'n stuff
$validation = $validOrNot[$json['result']['valid']];

answered May 26 '14 at 08:18

vascowhite

18,120
9
61
77

Turn 1/0 to valid/invalid

3 Answers3