Why does my code call a different method overload when using params?

Question

Why calls the compiler only the second function and not the first? I have no idea why it's taken the second function.

WriteLog("string", "string2" , "string3", "string4");

public static void WriteLog(string text, params string[] pAktionInfos)
{
    WriteLog(text, pAktionInfos);
}

public static void WriteLog(string text, string text2, params string[] pAktionInfos)
{
    if (string.IsNullOrEmpty(text2))
    {
        //Awesome Code
    }
    //Another Awesome Code
}

Its the closest match. The compiler can see you have four formal parameters, the first two of which are strings. The closeset match signature is the one with two formal string parameters. Just the way it is. — PhillipH, Aug 19 '14 at 14:29

score 4 · Accepted Answer · answered Aug 19 '14 at 14:28

4

Only one function can be called and the compiler calls the one that is closest to the original signature and most specific.

You should get a warning about those two functions anyway. If you don't, turn up your warning level.

answered Aug 19 '14 at 14:28

nvoigt

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score 1 · Answer 2 · answered Aug 19 '14 at 14:30

1

Because in the compiler the order of recognition goes from explicit parameters to parameters defined with params. The more specific a signature is, the sooner it matches.

answered Aug 19 '14 at 14:30

Patrick Hofman

153,850
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Why does my code call a different method overload when using params?

2 Answers2