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I am able to register a COM-DLL (written in VB6) dowFct.dll succesfully with

regsvr32 dowFct.dll

But when I try to do it with

regsvr32 dowFct.dll /i

I am getting the Error (translated from german to english):

The module dowfct.dll was loaded but the DllInstall entry point was not found.

I am asking me, if it is not the same to use regsvr32 with /i and without any additional parameter? Can someone help me in this case whats going wrong? - Thanks.

rekire
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BennoDual
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  • Possible duplicate of [What is the different between /n and /i parameters of RegSvr32.exe?](https://stackoverflow.com/questions/10990216/what-is-the-different-between-n-and-i-parameters-of-regsvr32-exe) – StayOnTarget Apr 19 '18 at 12:09

3 Answers3

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  • Without the /i option, regsvr32 loads the DLL and calls the exported function DllRegisterServer.
  • With the /i option, regsvr32 loads the DLL and calls the exported function DllInstall.

Clearly your DLL does not export DllInstall and so it would seem likely that it expects to be registered by a call to DllRegisterServer. So, omit the /i option when calling regsvr32.

The documentation for DllInstall explains the difference between these two functions:

DllInstall is used only for application installation and setup. It should not be called by an application. It is similar in purpose to DllRegisterServer or DllUnregisterServer. Unlike these functions, DllInstall takes an input string which can be used to specify a variety of different actions. This allows a DLL to be installed in more than one way, based on any criteria that is appropriate.

To use DllInstall with regsvr32, add a "/i" flag followed by a colon (:) and a string. The string will be passed to DllInstall as the pszCmdLine parameter. If you omit the colon and string, pszCmdLine will be set to NULL. The following example would be used to install a DLL.

regsvr32 /i:"Install_1" dllname.dll

DllInstall is invoked with bInstall set to TRUE and pszCmdLine set to "Install_1". To uninstall a DLL, use the following:

regsvr32 /u /i:"Install_1" dllname.dll

With both of the above examples, DllRegisterServer or DllUnregisterServer will also be called. To call DllInstall only, add a "/n" flag.

regsvr32 /n /i:"Install_1" dllname.dll
David Heffernan
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A VB6 COM DLL does not export DLLInstall() which is a function that serves as a way for a DLL to perform setup operations on itself (and is what /i tries to execute) so you do not need to worry about it.

Just use regsvr32 dowFct.dll (which calls DllRegisterServer() which the VB Compiler has added to the library for you.)

Alex K.
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Did you try to run regsvr32 /??

It shows me that there some attentional parameters are send to the DllInstall method of the dll file.

/i:cmdline : Calls DllInstall passing it an optional [cmdline]. When used with /u, it calls dll uninstall.

[source]

rekire
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  • I'm so far always assumed that dowFct.dll `regsvr32 /i dowFct.dll` is the same as `regsvr32 dowFct.dll`. Is not that so? – BennoDual Sep 29 '14 at 11:37
  • I'm not absolutly sure, but I guess that another method is called on the dll file but indeed without any input. – rekire Sep 29 '14 at 11:38