json_decode in php returns in unexpected form

Question

When using json_decode I am getting fields with unexpected strings. My json file is:

{
buyer_accepts_marketing: false,
cart_token: "eeafa272cebfd4b22385bc4b645e762c",
id: 327474488104976400,
}

and my relevant php code is

$info = json_decode($file,true);
print $info["id"];
echo "<br>";
print $info["cart_token"];

The Output I am getting is

3.2747448810498E+17

eeafa272cebfd4b22385bc4b645e762c

Why am I not getting the correct value of id?

Is this value coming from DB, I mean is a service bringing this data.? — MixedVeg, Nov 06 '14 at 04:53
To be exact, the json file was generated by a shopify webhook. — Abey, Nov 06 '14 at 04:56
The id type is an integer and the current value exceeds the integer range. — MixedVeg, Nov 06 '14 at 05:01
do a cast to string, as the value is a float although is looks like an integer — ajreal, Nov 06 '14 at 05:01
The range of Integer is [-2147483648, 2147483647] and the id value here exceeds it!+ — MixedVeg, Nov 06 '14 at 05:03
The gist: more recent PHP versions allow for `JSON_BIGINT_AS_STRING`. — mario, Nov 06 '14 at 05:05

Sougata Bose · Answer 1 · 2014-11-06T05:09:26.810

0

It happening because the value of id is out of the range. Try to create it as string. if it is changed to string then it will work properly.

Integer overflow

If PHP encounters a number beyond the bounds of the integer type, it will be interpreted as a float instead. Also, an operation which results in a number beyond the bounds of the integer type will return a float instead.

edited Nov 06 '14 at 05:09

answered Nov 06 '14 at 05:02

Sougata Bose

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Tkz.. preg_replace was the best solution. – Abey Nov 06 '14 at 05:24

json_decode in php returns in unexpected form

1 Answers1