Why is my int() function not working python 2.7

Question

def game():    

modex = False
while modex == False:
    mode = raw_input("please select a mode: ")
    try:
    ## THE PROBLEM IS HERE!
        int(mode)
        if mode == 1:
            modex = True
            break
        elif mode == 2:
            modex = True
            break
        elif mode == 3:
            modex = True
            break
        else:
            print "invalid #. try again"
            modex == False
            continue

    except:
        print "invalid # try again"
        continue
game()

i can't seem to turn mode into an integer, for example:

input: 1 output: invalid # try again

for the game i am making i have 3 modes hence the 3 modes if statement in the try-except statement

could you please help me? I am using python 2.7

either use `modex` or `break`. That is, use `break`. The `continue` is unnecessary. — Daniel, Jan 04 '15 at 19:00
`while True` will do the same thing, modex is redundant, you also don't seem to return anything so I don't see what the function is actually doing. — Padraic Cunningham, Jan 04 '15 at 19:03

score 1 · Accepted Answer · answered Jan 04 '15 at 18:55

1

Asign the int(mode) value to something. Best approach: mode = int(mode)

You can also try: mode = int(raw_input:('please select a mode:'))

answered Jan 04 '15 at 18:55

implicati0n

269
2
10

Thanks toni my code is now working! – Telekey Jan 04 '15 at 19:08

Why is my int() function not working python 2.7

1 Answers1