How to make pattern for string in android

Question

I want make own pattern matcher.

I want allow like this characters only TN 08 AB 2233. How can I make a pattern for this?

I tried like below but its erase all characters what I type in edit text

^[A-Z]{1,2}[0-9]{4,5}[A-Z]{7,8}[0-9]{10,13}$

Thanks.

See http://stackoverflow.com/questions/2763022/android-how-can-i-validate-edittext-input/11838715#11838715 — kranthi117, Sep 03 '15 at 06:27
http://stackoverflow.com/questions/10327901/how-to-use-regular-expression-in-android — IntelliJ Amiya, Sep 03 '15 at 06:30
`{7,8}` repeats the previous token 7 or 8 times. It won't denote the position. — Avinash Raj, Sep 03 '15 at 06:48

score 0 · Answer 1 · answered Sep 03 '15 at 06:46

0

Try this,

 ^[A-Z]{2}[ -][0-9]{1,2}(?: [A-Z])?(?: [A-Z]*)? [0-9]{4}$

Hope this will work for you.

answered Sep 03 '15 at 06:46

Amit Gupta

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score 0 · Answer 2 · answered Sep 03 '15 at 06:48

what you are looking for is something like this ^[A-Z]{2}\\s\\d{2}\\s[A-Z]{2}\\s\\d{4}$

for explanation, the values in the curly brackets are not idices, but number of values.

so, [A-Z]{1,2} means a value between A-Z at least ond and max two times. [0-9]{4,5} means a value between 0 an 9 at least 4 and max 5 times. also you are missing the white spaces in your regex, if they are mandatory. \s defines any white space, the second \ is to escape the other \. if the are not mandatory, you can ignore them by a ? like this ^[A-Z]{2}(\\s)?\\d{2}(\\s)?[A-Z]{2}(\\s)?\\d{4}$. so they can be there, but do not have to be.

How to make pattern for string in android

2 Answers2