PHP date actual year

Question

I have this:

$startdate = date("Y-m-d", strtotime('2015-' . $startmonth . '-01'));

But instead of filling in the year, how do I get the current year?

http://stackoverflow.com/questions/64003/how-do-i-use-php-to-get-the-current-year — Denis Frezzato, Dec 16 '15 at 11:14
date("Y-m-d", strtotime( date('Y') . '-' . $startmonth . '-01')); — ‌‌R‌‌‌., Dec 16 '15 at 11:15

score 5 · Accepted Answer · answered Dec 16 '15 at 11:17

5

You can use date('Y')

$startdate = date("Y-m-d", strtotime(date('Y') . '-' . $startmonth . '-01'));

answered Dec 16 '15 at 11:17

rccoros

score 2 · Answer 2 · answered Dec 16 '15 at 11:18

2

You can use date, since the year will remain a year. for instance,

<?php echo date("Y"); ?>

Personal experience in researching in Google.

answered Dec 16 '15 at 11:18

@Denis Frezzato already comment out the link for the answer, and he want month and day as well – vishal Dec 16 '15 at 11:20

2 Answers2