SIGFPE Error in C?

Question

I have the following code which calculates the number of trailing zeroes in factorial of a number. The program runs for the first testcase which is 10 but when the same code is run for 17 it shows a SIGFPE error in C? Can anyone tell where i am going wrong?

#include<stdio.h>
#include<math.h>
int main(){
    int n,i=1,j,sum=0,l;
    scanf("%d",&n);
    while((n/(5^i))>1)
    {
        j=(n/(5^i));
        i++;
        sum=sum+j;
    }
    printf("%d",sum);
    return 0;
}

Step through the program with your debugger and analyse your values to find where you're going wrong. Also, don't tag the wrong language — Lightness Races in Orbit, Apr 02 '16 at 22:32

score 0 · Accepted Answer · answered Apr 02 '16 at 22:35

0

What is wrong is that you are using the operator ^ the wrong way: it is not the power operator, but the bitwise XOR operator. There is no power operator in C, but a pow() function the math library.

On the other way... where the factorial is calculated?

answered Apr 02 '16 at 22:35

mcleod_ideafix

11,128
2
24
32

thanks! worked like a charm. What a foolish mistake thanks for pointing it out :) – Anidh Singh Apr 02 '16 at 22:38
1

There is no need to calculate the factorial! The trailing zeroes could be calculated with the help of the number only. – Anidh Singh Apr 02 '16 at 22:40

SIGFPE Error in C?

1 Answers1