Simple for loop not working in C

Question

I'm trying to get my program to repeat the letter "a" 255 times, but for some reason this prints "a" just once and then stops.

#include <stdio.h>
int main(){
    for(int e = 0; e < 253; e++);
    {
        printf("a");
    }
    printf("\n");
    return 0;
}

please see this post - http://stackoverflow.com/questions/13421395/effect-of-semicolon-after-for-loop — Wasi Ahmad, Dec 23 '16 at 04:39
`for(int e = 0; e < 253; e++);` --> `for(int e = 0; e < 255; e++)` — BLUEPIXY, Dec 23 '16 at 04:43

Vimbuddy · Accepted Answer · 2016-12-23T04:37:59.313

2

This is how you should do it.

#include <stdio.h>
int main(){
    for(int e = 0; e < 253; e++)
    {
            printf("a");
    }
    printf("\n");
    return 0;
}

edited Dec 23 '16 at 04:37

answered Dec 23 '16 at 04:37

Vimbuddy

166
3
19

3

Vote to close for typo. Questions like that don't need an answer. – R Sahu Dec 23 '16 at 04:38
@RSahu Okay. I'll keep that in mind. Thanks – Vimbuddy Dec 23 '16 at 04:40

score 2 · Answer 2 · answered Dec 23 '16 at 04:38

2

There is a semicolon end of this loop for(int e = 0; e < 253; e++);. The for loop just runs without doing anything. Finally the rest of the statement gets executed and you get only one print.

answered Dec 23 '16 at 04:38

haasi84

104
3

3

Vote to close for typo. Questions like that don't need an answer. – R Sahu Dec 23 '16 at 04:39

Simple for loop not working in C

2 Answers2