Failed to open stream: Invalid argument when using PHP fopen()

Question

Whenever I run some code in PHP, I get these warnings:

Warning: fopen(extfiles/
Notice: Undefined offset: 1 in C:\filepath\file.java): failed to open stream: Invalid argument in C:\filepath\file.php on line 82 Warning: feof() expects parameter 1 to be resource, boolean given in C:\filepath\file.php on line 84
Warning: fgets() expects parameter 1 to be resource, boolean given in C:\filepath\file.php on line 87

The lines from the code:

$filenamee = $_POST["filename"];
$folder = $_POST["folder"];

$var1 = explode(".", $filenamee);
$var2 = explode(".", $folder);

$filename = "extfiles/".$var2[0]."/".$var1[0].".java";
$file = fopen($filename, "c"); // This is line 82
$lines_array = array();
while (!feof($file)) { // This is line 84


    $line = fgets($file); // This is line 87
    array_push($lines_array, $line);

}

The code needs to create and edit Java file, but the problem is that it isn't creating it. Whenever I run this code, I get the last 2 warnings lots of times...

What can I do in order to solve it?

You should have checked whether the file exists or not using `file_exists()` function. Because the error suggests that the file doesn't exist. — Muntashir Akon, Feb 28 '17 at 15:24
I know that the file **isn't** exist. I want to create it and write into it — Ido, Feb 28 '17 at 15:25
`fopen` doesn't create directories: http://stackoverflow.com/questions/5337854/php-fopen-to-create-folders — Muntashir Akon, Feb 28 '17 at 15:30
But then I still get the 2 last errors, with `string` written instead of `boolean`... — Ido, Feb 28 '17 at 15:35
That means `$file` is a string value which isn't true. `fopen` doesn't return any string value (either resource or false). Be sure to check for possible errors. — Muntashir Akon, Feb 28 '17 at 15:58

score 0 · Answer 1 · answered Feb 28 '17 at 15:16

0

It sounds like the script can not find the file to open. extfiles/ works from the directory the php file is located in. Can we get a tree view of your dir structure? Typically you'll want to define the entire file path from the root of the drive upward.

answered Feb 28 '17 at 15:16

David J Eddy

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`exfiles` folder is in the same directory as `file.php`. – Ido Feb 28 '17 at 15:23
if it's in the same directory, why include it? should be like this then: $filename = $var2[0]."/".$var1[0].".java"; – Jens Kooij Feb 28 '17 at 16:04
No, it's `filepath/file.php`, and `filepath/extfiles/file.java`. – Ido Feb 28 '17 at 16:28

Failed to open stream: Invalid argument when using PHP fopen()

1 Answers1