Access variable from another file

Question

I have ex1.js and ex2.js. And in ex2.js I want to get variable which one is in ex1.js

I can read the file, but I want to get exactly this var Value.

 var fs = require('fs');
 var readMe = fs.readFileSync('path', 'utf8');
 console.log(readMe);

You shouldnt explain the problem on the title. Title are just keywords — xsami, Jun 09 '17 at 13:18
I mean inside of file there are a lot of variables and I want to get one of them and change it — Dima, Jun 09 '17 at 13:25
There are no variables to the return value of readFileSync. It just returns you a buffer and you can do whatever you want with it. It returns you a buffer object which is a child of ArrayBuffer. — Arpit Solanki, Jun 09 '17 at 13:36
thanks for answer.I didn't know about it. Do you know how can I take the variable from another file and replace it? — Dima, Jun 09 '17 at 13:39
there is the var Url = "https://....." I want to change the value of the Url — Dima, Jun 09 '17 at 13:43
yes,can I do it withoud reading the file ?Or how can i do it? — Dima, Jun 09 '17 at 13:46
i don't think you can do it without reading the file. Just read the file modify the content and write it back. — Arpit Solanki, Jun 09 '17 at 13:47
fs.readFile('C:/Users/user/.....js', function(error, buffer) — Dima, Jun 09 '17 at 14:03
Get one thing clear, that is not just text file. That is **code file**. You don't read it like text, you compile it. Use [`require`](https://stackoverflow.com/questions/9146980/how-can-i-pass-a-variable-while-using-require-in-node-js) — Shaharyar, Jun 09 '17 at 19:05

score 0 · Answer 1 · answered Jun 09 '17 at 18:57

0

As long as they are both JavaScript files this is how it is generally done.

// in the js2 file
exports.var_js2 = 15;

// in the js1 file
var_js2 = require('./js2').var_js2

answered Jun 09 '17 at 18:57

bezzoon

1 Answers1