find and replace keywords with urls ONLY if not already wrapped in a url

Question

So, I can easily do this:

$keywords = array(' jacket ',' sweater ',);
$urls = array(' <a href="#">jacket</a> ',' <a href="#">sweater</a> ',);
$content = str_ireplace($keywords,$urls,$content);

But the problem is when something like jacket or sweater is already in a link tag.

I can't think of any simple solutions to this...

score 0 · Accepted Answer · answered Dec 23 '10 at 20:20

0

step 1) find all instances of each keyword which are within a url & replace them with a GUID
step 2) replace all other instances of each keyword with thier replacement
step 3) replace the GUID's with their origional keywords.

Hope you choose your Guid's and how you do your searching is up to you :)

answered Dec 23 '10 at 20:20

GreyCloud

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Thanks, I'm going to try this a bit later, I'll update this post if I get something functional... – dismalist Dec 23 '10 at 22:22

score 0 · Answer 2 · answered Dec 23 '10 at 21:03

You might be able to construct a fancy regex for this, but it would be extremely complicated and nearly impossible to maintain. IMO, you should take a token-based approach to solve this problem. I have a project called Lexentity that we use to replace apostrophes and quotes, etc., with their numerical entities. You could probably adapt that code for your purposes. There's also a HTMLTokenizer (and HTMLTokenset) in Habari that you might find useful.

Thanks, I'm going to check it out. – dismalist Dec 23 '10 at 22:22 — dismalist, Dec 23 '10 at 22:22

find and replace keywords with urls ONLY if not already wrapped in a url

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