% scala
Welcome to Scala 2.12.3 (Java HotSpot(TM) 64-Bit Server VM, Java 1.8.0_111).
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scala> trait Op[-Y, -Z, +A, +B] {
| def apply(other: (Y, Z)): (A, B)
| }
defined trait Op
scala> implicit class RichTuple2[+A, +B](t: (A, B)) {
| def ~~~(other: Int): (A, B) = ???
| def ~~~[RA, RB](other: Op[A, B, RA, RB]): (RA, RB) = other.apply(t)
| }
defined class RichTuple2
scala> def swap[A, B] = new Op[A, B, B, A] {
| override def apply(other: (A, B)) = (other._2, other._1)
| }
swap: [A, B]=> Op[A,B,B,A]
scala> (1, "foo") ~~~ swap
<console>:14: error: overloaded method value ~~~ with alternatives:
[RA, RB](other: Op[Int,String,RA,RB])(RA, RB) <and>
(other: Int)(Int, String)
cannot be applied to (Op[Nothing,Nothing,Nothing,Nothing])
(1, "foo") ~~~ swap
If I remove the first ~~~(other: Int)
method, then it works:
scala> trait Op[-Y, -Z, +A, +B] {
| def apply(other: (Y, Z)): (A, B)
| }
defined trait Op
scala> implicit class RichTuple2[+A, +B](t: (A, B)) {
| def ~~~[RA, RB](other: Op[A, B, RA, RB]): (RA, RB) = other.apply(t)
| }
defined class RichTuple2
scala> def swap[A, B] = new Op[A, B, B, A] {
| override def apply(other: (A, B)) = (other._2, other._1)
| }
swap: [A, B]=> Op[A,B,B,A]
scala> (1, "foo") ~~~ swap
res0: (String, Int) = (foo,1)
The question is why type inference and method selection fails in this case? The method ~~~(other: Int)
takes a parameter that isn't at all related to the type of swap
(with is an Op
type). And is anyone aware of a workaround?