Path separators are missing

Question

I'm trying to implement the selection of a local file and send its path to js.

_mainWindow.Browser.ExecuteScriptAsync(
  "document.getElementById('location').value=" + 
  '\'' + openFileDialog.FileName + '\'');

this option returns a path without delimiters - "PathTofile", although the path itself is written to the file - "Path\To\File". tell me, please, what am I doing wrong?

@Aria Oh, sorry... I need execute script path to file with backslashes - "Path\To\File", but my script return me - "PathToFile", please, tell me what the problem is ? — Елизавета, Nov 12 '17 at 10:29
@Елизавета so edit your question, you are getting more down vote unless you edit and translate it to English. — Aria, Nov 12 '17 at 10:31
What is the **exact** value of `openFileDialog.FileName`? Also have a read of https://stackoverflow.com/questions/3903488/javascript-backslash-in-variables-is-causing-an-error . — mjwills, Nov 12 '17 at 10:36
@mjwills https://cdn1.savepice.ru/uploads/2017/11/12/ed51a05d72fa5df7b273c4539dbae085-full.png — Елизавета, Nov 12 '17 at 10:48
Yes, your value only has single slashes in it, not double. Use `_mainWindow.Browser.ExecuteScriptAsync( "document.getElementById('location').value=" + '\'' + openFileDialog.FileName.Replace(@"\", @"\\") + '\'');` — mjwills, Nov 12 '17 at 10:51

score 1 · Answer 1 · answered Nov 12 '17 at 11:07

1

_mainWindow.Browser.ExecuteScriptAsync( "document.getElementById('location').value=" + '\'' + openFileDialog.FileName.Replace(@"\", @"\\") + '\'');

Thank's you!

answered Nov 12 '17 at 11:07

Елизавета

115
3

You are welcome. I'll add my original comment as an answer. – mjwills Nov 12 '17 at 11:17

score 1 · Accepted Answer · answered Nov 12 '17 at 11:14

The issue is that your FileName has single slashes in it. JS will interpret those slashes as escape characters.

The simplest solution is to replace your single slashes with double slashes:

_mainWindow.Browser.ExecuteScriptAsync(
    "document.getElementById('location').value=" + '\''
        + openFileDialog.FileName.Replace(@"\", @"\\") + '\'');

Path separators are missing

2 Answers2