I am using react native and I have a situation where I navigate to a new component using react navigation v2 stack navigator. The user then presses an option and goes back to the original screen they were at with updated information.
My question is how do change the state of the previous screen so it shows the information the user selected?
ShowFruitPage.js
This page shows a list of fruits that the user picked.
export default class ShowFruitPage extends Component{
constructor(){
super();
this.state = {
List: [{Fruit: apple}]
}
}
render(){
return(
<View style={styles.ViewStyle}>
<FlatList
data={this.state.List}
renderItem={({item}) =>
<TouchableNativeFeedback
background={TouchableNativeFeedback.Ripple('grey')}
onPress={() => this.props.navigation.navigate('AddFruit',
{
List: this.state.List
})}
<View style={styles.ListView}>
<Text>{item.Fruit}</Text>
</View>
</TouchableNativeFeedback>
}
/>
</View>
)
}
}
AddFruit.js
This page shows a list of available fruits the user can pick. When the user picks from this list I want to update the list on the ShowFruitPage.
export default class AddFruit extends Component{
constructor(){
super();
this.state = {
FruitList: [{Fruit:orange}, {Fruit: pear}]
}
this.pickFruit = this.pickFruit.bind(this);
}
pickFruit(Fruit){
//Add the picked fruit to the ShowFruitPage state List
//Then Navigate back to ShowFruitPage
this.props.navigation.navigate('ShowFruitPage')
}
render(){
return(
<View style={styles.ViewStyle}>
<FlatList
data={this.state.FruitList}
renderItem={({item}) =>
<TouchableNativeFeedback
background={TouchableNativeFeedback.Ripple('grey')}
onPress={() => this.pickFruit(item)}
<View style={styles.ListView}>
<Text>{item.Fruit}</Text>
</View>
</TouchableNativeFeedback>
}
/>
</View>
)
}
}