how do I ignore NA when I make logical indexing in R?

Asked Oct 01 '18 at 19:37

Active Oct 01 '18 at 19:40

Viewed 40 times

n = c(1, 3, NA) 
s = c("aa", "bb", "cc") 
b = c(TRUE, FALSE, TRUE) 
df = data.frame(n, s, b)
k = df$n >= 2
df2 <- df[k,]

I want to find n is larger than 2. so I made k. If I run it:

.   n    s     b
2   3   bb   FALSE
NA NA   NA     NA

The result is above:
In this situation, I want to see a result without NA: what should I do?

edited Oct 01 '18 at 19:40

markus

asked Oct 01 '18 at 19:37

Shawn

1

Use `k <- which(df$n >= 2)` – user3640617 Oct 01 '18 at 19:41
Fyi, some alternative interfaces (with packages data.table or dplyr) would ignore the NAs here. – Frank Oct 01 '18 at 19:43
2

Even in base, `subset(df, n >= 2)` doesn't include the `NA` row. – Gregor Thomas Oct 01 '18 at 19:46

0 Answers0