how to get out of nested loop and continue with iteration of outer loop

Question

Write a python function, find_ten_substring(num_str) which accepts a string and returns the list of 10-sub strings of that string.

A 10-sub string of a number is a sub string of its digits that sum up to 10. sample input='3523014' actual output=['5230', '23014', '523', '352']

i have tried the below code it is printing only one sub string that adds up 10 (only [28])and then terminating.

def find_ten_substring(num_str):
    sumi=0
    list1=[]
    substr=''
    for i in range(0,len(num_str)):
        for j in range(i,len(num_str)):
            sumi=sumi+int(num_str[j])
            substr=substr+num_str[j]
            if(sumi==10):
                list1.append(substr)
                print(list1)
                break
        sumi=0
        substr=''
        continue

num_str="2825302"
print("The number is:",num_str)
result_list=find_ten_substring(num_str)
print(result_list)

score 1 · Accepted Answer · answered Jun 26 '19 at 17:31

You specifically told it to quit as soon as it found that one solution. Look at the bottom of your outer loop:

sumi=0
substr=''
break

This resets the accumulation variables, but then breaks the loop rather than repeating. Remove the break and return to your code development -- you have other errors, starting with lack of any return value.

Also, you should learn basic debugging. For starters, a few print statements inside your code can trace the data and control flow. See this lovely debug blog for help.

how to get out of nested loop and continue with iteration of outer loop

1 Answers1