how can i find the next min number in dictionary list

Question

I want to find the next minimum value of the dictionary i wrote this code but it seems like there is an error with for loop any help ??

nodesdistfromsmartmeter = {'nodeA': 100, 'nodeB': 250, 'nodec': 300, 'nodeD': 50}

min_dist=min(nodesdistfromsmartmeter,key=nodesdistfromsmartmeter.get)
print("smalistdist",min_dist)
seondmin=0
for v in nodesdistfromsmartmeter():
 if(v>seondmin and v>min_dist):
    seondmin=v
    print(seondmin)

Next min as in 100 in your example? – andreis11 Apr 03 '20 at 21:28 — andreis11, Apr 03 '20 at 21:28

Hamza Khurshid · Answer 1 · 2020-04-04T06:58:34.407

Try this, it has some errors fixed.

nodesdistfromsmartmeter = {'nodeA': 100, 'nodeB': 250, 'nodec': 300, 'nodeD': 50}

min_dist=min(nodesdistfromsmartmeter,key=nodesdistfromsmartmeter.get)
print("smalistdist",min_dist)
secondmin=0
for v in nodesdistfromsmartmeter.keys():
 if(nodesdistfromsmartmeter[v]>secondmin and nodesdistfromsmartmeter[v]>nodesdistfromsmartmeter[min_dist]):
    secondmin=nodesdistfromsmartmeter[v]
    print(seondmin)

Output:

smalistdist nodeD
100
250
300

score 1 · Answer 2 · answered Apr 03 '20 at 21:34

1

Hope this helps :

from heapq import nsmallest

my_dict = {'nodeA': 100, 'nodeB': 250, 'nodec': 300, 'nodeD': 50}

print(nsmallest(2, my_dict.values())[-1])

answered Apr 03 '20 at 21:34

AmirHmZ

516
3
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score 0 · Answer 3 · edited Oct 29 '21 at 06:21

0

You just need to change this:

for v in nodesdistfromsmartmeter():

For this:

for v in nodesdistfromsmartmeter.values():

edited Oct 29 '21 at 06:21

Nimantha

6,405
6
28
69

answered Apr 03 '20 at 21:28

EnriqueBet

1,482
2
15
23

still gives me an error – Apr 03 '20 at 21:32
it turned to this error if(v>seondmin and v>min_dist): TypeError: '>' not supported between instances of 'str' and 'int' – Apr 03 '20 at 21:34
I updated my answer – EnriqueBet Apr 03 '20 at 21:36

how can i find the next min number in dictionary list

3 Answers3