Running tsc with --declaration option generates the .d.ts file with all the declaration, private included.
Is there a way to produce a .d.ts file with only exported types and, for classes, only public methods and attributes?
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Daniele Ricci
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It's not possible.
Typescript keeps privates in generated .d.ts files to support further inheritance.
Because there is no such thing as 'private' in JS, declaring a type that derives from a d.ts type with stripped out privates could cause problems if you accidentally will have a name collision in your child class. That will be very difficult to find and fix.
Yuriy Naydenov
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You confirmed my suspect – Daniele Ricci Jun 14 '20 at 11:59
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1Not not possible anymore - TS 3.8+ supports true private properties and respects the private status of these fields. But the scope is limited to those true private properties - `private` and `/** @private */` marked properties are emitted as usual. – Oleg Valter is with Ukraine Aug 31 '21 at 03:13