fun A(){
thread {
Thread.sleep(1000)
//MyCode
}
}
fun B(){
thread {
//MyCode
}
}
}
need to call 1st A() then B() with Rxjava . is there any operator that i can use?
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1have you tried using flatmap ? – a_local_nobody Jan 20 '21 at 16:23
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How to use that in kotlin??? – sunny kumar Jan 20 '21 at 16:24
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there are lots of resources available, what have you tried so far ? – a_local_nobody Jan 20 '21 at 16:25
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https://stackoverflow.com/questions/33471526/why-do-we-need-to-use-flatmap – a_local_nobody Jan 20 '21 at 16:26
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1i am ver new to rxjava java ....can you share any resource – sunny kumar Jan 20 '21 at 16:26
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you can't ask for resources on stack overflow, that's just a rule, but i have shared with you another stack overflow link which i believe will help get you started – a_local_nobody Jan 20 '21 at 16:27
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Single.fromCallable { A() }.flatMap(it -> {B()}).subscribeOn(AndroidSchedulers.mainThread()) .observeOn(AndroidSchedulers.mainThread()) .subscribe({ value -> }) { error -> } – sunny kumar Jan 20 '21 at 18:06
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not working..... – sunny kumar Jan 20 '21 at 18:07