I was attempting to create an array from user input in C. My code was as follows
#include <stdio.h>
#include <stdlib.h>
char** create_array(int num);
int main(){
char** my_array;
int i;
printf("%s", "Input the size of the array: ");
scanf("%d", &i);
my_array = create_array(i);
for (int m = 0; m < i; m++){
printf("%s\n", (char*)my_array[m]);
}
}
char ** create_array(int num){
char** array = malloc(num * sizeof(char*));
for (int i = 0; i < num; i++) {
char temp[32];
printf("Input element %d of the array: ", i);
scanf("%s", temp);
array[i] = temp;
}
for (int m = 0; m < num; m++){
printf("%s\n", array[m]);
}
printf("end of func\n");
return array;
}
I was having (possibly unrelated?) issues with segmentation faults until I replaced the declaration of temp
from char *temp;
to char temp[32];
. I am not sure of why declaring temp
as a char pointer creates the segmentation fault, if that is a simple related answer let me know, if not I will ask in another question.
However, when I run this code, upon inputting
Input the size of the array: 2
Input element 0 of the array: value0
Input element 1 of the array: value1
I get
value1
value1
end of func
Segmentation fault (core dumped)
So to me it seems like temp somehow isn't changing when the for loop executes next iteration. I'm not sure why or how that would ever happen though. I also tried changing
printf("%s\n", my_array[m]);
to
printf("%s\n", (char*)my_array[m]);
but that didn't seem to help either.
Any ideas? Thanks