HTTPError + Request

Asked Oct 17 '22 at 13:48

Active Oct 17 '22 at 13:52

Viewed 50 times

Hej to all.

Need help. I need send request, if request link not correct - I need to recive false but something wrong in the code. Can someone help ?

from urllib.error import HTTPError
import requests

def form_url(urlcheck):
    try:
        y = requests.get(urlcheck)
    except HTTPError:
        return False
    if y == 200 or 403:
        return True


print(form_url("https://stackoverflow.com/"))

print(form_url("https://stackoverflowFALSE.com/")) # WRONL LINK NEED RECEVE FALSE

edited Oct 17 '22 at 13:52

asked Oct 17 '22 at 13:48

Everyone make mistakes

do `except requests.exceptions.RequestException:` – Tom McLean Oct 17 '22 at 13:51
1

Thanks. You are best. All working .!!!! – Everyone make mistakes Oct 17 '22 at 13:53
Does this answer your question? [Correct way to try/except using Python requests module?](https://stackoverflow.com/questions/16511337/correct-way-to-try-except-using-python-requests-module) – pigrammer Oct 17 '22 at 13:56
Yes. Much more information with details and explanation. Thanks a lot. – Everyone make mistakes Oct 17 '22 at 21:20

HTTPError + Request

0 Answers0