How to use a for loop to print every other item in a list?

Question

I have a list named "ul_children", I need to use a for loop to print every other item in that list starting with the second item or the index[1]. I am new to for loops in python and I am struggling with this.

I have tried a few different things I thought would work, but I have been unsuccessful so far. Any help would be appreciated.

The closest I have gotten so far is by using:

i = 1
for li in ul_children: 
   print(ul_children[i])

but I don't know how to get 'i' to increase each time the loop is performed.

Please provide what you have tried so far. You should have a look at the built-in function [`range()`](https://www.w3schools.com/python/ref_func_range.asp). — Mushroomator, Nov 16 '22 at 22:09
https://stackoverflow.com/questions/8865878/skipping-every-other-element-after-the-first — Captain Caveman, Nov 16 '22 at 22:18

Ojedalatronico · Answer 1 · 2022-11-16T22:16:42.493

1

You can do it like this:

ul_children = ["r","a","t","o","n"]

for i in ul_children[1:]:

    print(i)

edited Nov 16 '22 at 22:16

answered Nov 16 '22 at 22:15

Ojedalatronico

11
3

How to use a for loop to print every other item in a list?

1 Answers1