Useless setTimeout call (missing quotes around argument?)

Question

I have this sniplet of code in jQuery

$element.parent().children().last().hide().show('slide', {direction : 'left'}, 700, function () {
    $element.delay(2000, function() {
        $element.parent().children().last().hide('slide', {direction: 'left'}, 700);             
        reload_table(question_number);
        //delay ends here
    });
});

delay is declared as:

jQuery.fn.delay = function(time,func){
    return this.each(function(){
        setTimeout(func,time);
    });
};

Now I get the error:

useless setTimeout call (missing quotes around argument?)

FF3.x, Firefox 6+ is ok. Any ideas on that? Why could this be happening?

score 17 · Answer 1 · answered Dec 07 '12 at 07:20

17

I got same error when I wrote

setTimeout(updateStatus(), 5000);

instead of

setTimeout(updateStatus, 5000);

answered Dec 07 '12 at 07:20

wsbaser

1,178
10
7

OP is already calling the method correctly! this is not the issue. He is already passing a pointer to a function, in the first argument. – gcb Sep 04 '13 at 16:05

score 10 · Answer 2 · answered Aug 01 '13 at 14:09

I agree with wsbaser. I had the additional instance of needed to pass information to the function, and for simplicity used:

setTimeout(function(){ updateStatus(myData) } , 5000);

The argument needs to be a function and not a function being called. Firefox caught this error, chrome let it go.

score 7 · Answer 3 · answered Jul 24 '12 at 13:44

Just for reference if someone stumbles upon this question and is looking for a possible answer. I got the exact same error message as the initial poster because I was mixing up the setTimeout arguments order.

This:

setTimeout(25, function(){
    spotlight.intro.find('#intro').ellipsis();  
});

... gave me the error message. I changed the function to this:

setTimeout(function(){
    spotlight.intro.find('#intro').ellipsis();
}, 25);

And my problem was solved.

Dr.Molle · Accepted Answer · 2011-11-21T11:56:22.007

6

There already exists a jQuery-method delay and it expects a string(queueName) and not a function as parameter. Choose another name for your delay-method to avoid conflicts.

edited Nov 21 '11 at 11:56

answered Nov 21 '11 at 11:47

Dr.Molle

116,463
16
195
201

sorry to say that but that didnt fix it – kosta5 Nov 23 '11 at 09:09

kosta5 · Answer 5 · 2012-07-26T13:39:24.990

-1

The problem was in Firefox 3. It is not handling some elements properly => Element is completely omitted in the tree and ignored -> hence my original problem

edited Jul 26 '12 at 13:39

answered Nov 23 '11 at 09:23

kosta5

1,129
3
14
36

5

Very unhelpful and undescriptive answer. – Cyprus106 Jun 19 '12 at 17:59

Useless setTimeout call (missing quotes around argument?)

5 Answers5

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