1998 ATP Tour World Championships – Doubles

		Eltingh Haarhuis	Woodbridge Woodforde	Ferreira Leach	Delaître Santoro	RR W–L	Set W–L	Game W–L	Standings
1	Jacco Eltingh Paul Haarhuis		7–6(7–3), 6–4	6–4, 6–4	4–6, 7–5, 7–5	3–0	6–1	43–34	1
3	Todd Woodbridge Mark Woodforde	6–7(3–7), 4–6		6–7(3–7), 3–6	7–6(7–1), 3–6, 4–6	0–3	1–6	33–44	4
5	Ellis Ferreira Rick Leach	4–6, 4–6	7–6(7–3), 6–3		6–7(1–7), 6–4, 6–7(3–7)	1–2	3–4	39–39	3
7	Olivier Delaître Fabrice Santoro	6–4, 5–7, 5–7	6–7(1–7), 6–3, 6–4	7–6(7–1), 4–6, 7–6(7–3)		2–1	5–4	52–50	2

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

		Bhupathi Paes Eagle Florent	Knowles Nestor	Stolle Suk	Johnson Montana	RR W–L	Set W–L	Game W–L	Standings
2 9	Mahesh Bhupathi Leander Paes Joshua Eagle Andrew Florent		7–6(7–5), 6–0 (w/ Eagle / Florent)	6–4, 3–6, 4–6 (w/ Bhupathi / Paes)	6–3, 4–6, 6–7(4–7) (w/ Bhupathi / Paes)	0–2 1–0	2–4 2–0	29–32 13–6	5 4
4	Mark Knowles Daniel Nestor	6–7(5–7), 0–6 (w/ Eagle / Florent)		2–6, 6–4, 6–2	6–3, 6–2	2–1	4–3	32–30	1
6	Sandon Stolle Cyril Suk	4–6, 6–3, 6–4 (w/ Bhupathi / Paes)	6–2, 4–6, 2–6		7–6(8–6), 6–7(5–7), 6–7(4–7)	1–2	4–5	47–47	3
8	Donald Johnson Francisco Montana	3–6, 6–4, 7–6(7–4) (w/ Bhupathi / Paes)	3–6, 2–6	6–7(6–8), 7–6(7–5), 7–6(7–4)		2–1	4–4	41–47	2

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.